5(t+4)=5(2t-1)

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Solution for 5(t+4)=5(2t-1) equation: 



5(t+4)=5(2t-1)

We move all terms to the left:

5(t+4)-(5(2t-1))=0

We multiply parentheses

5t-(5(2t-1))+20=0



We calculate terms in parentheses: -(5(2t-1)), so:

5(2t-1)

We multiply parentheses

10t-5

Back to the equation:

-(10t-5)



We get rid of parentheses

5t-10t+5+20=0

We add all the numbers together, and all the variables

-5t+25=0

We move all terms containing t to the left, all other terms to the right

-5t=-25

t=-25/-5

t=+5

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