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5(t+5)-(-10)=50
We move all terms to the left:
5(t+5)-(-10)-(50)=0
determiningTheFunctionDomain 5(t+5)-50-(-10)=0
We add all the numbers together, and all the variables
5(t+5)-40=0
We multiply parentheses
5t+25-40=0
We add all the numbers together, and all the variables
5t-15=0
We move all terms containing t to the left, all other terms to the right
5t=15
t=15/5
t=3
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