5(t+6)-2(7t-5)=-10(t-2)+8

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Solution for 5(t+6)-2(7t-5)=-10(t-2)+8 equation: 



5(t+6)-2(7t-5)=-10(t-2)+8

We move all terms to the left:

5(t+6)-2(7t-5)-(-10(t-2)+8)=0

We multiply parentheses

5t-14t-(-10(t-2)+8)+30+10=0



We calculate terms in parentheses: -(-10(t-2)+8), so:

-10(t-2)+8

We multiply parentheses

-10t+20+8

We add all the numbers together, and all the variables

-10t+28

Back to the equation:

-(-10t+28)



We add all the numbers together, and all the variables

-9t-(-10t+28)+40=0

We get rid of parentheses

-9t+10t-28+40=0

We add all the numbers together, and all the variables

t+12=0

We move all terms containing t to the left, all other terms to the right

t=-12

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