5(t-1)=2(t+8)

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Solution for 5(t-1)=2(t+8) equation: 



5(t-1)=2(t+8)

We move all terms to the left:

5(t-1)-(2(t+8))=0

We multiply parentheses

5t-(2(t+8))-5=0



We calculate terms in parentheses: -(2(t+8)), so:

2(t+8)

We multiply parentheses

2t+16

Back to the equation:

-(2t+16)



We get rid of parentheses

5t-2t-16-5=0

We add all the numbers together, and all the variables

3t-21=0

We move all terms containing t to the left, all other terms to the right

3t=21

t=21/3

t=7

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