5(t-2)+5t=5(2t+2)-9

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Solution for 5(t-2)+5t=5(2t+2)-9 equation:


Simplifying
5(t + -2) + 5t = 5(2t + 2) + -9

Reorder the terms:
5(-2 + t) + 5t = 5(2t + 2) + -9
(-2 * 5 + t * 5) + 5t = 5(2t + 2) + -9
(-10 + 5t) + 5t = 5(2t + 2) + -9

Combine like terms: 5t + 5t = 10t
-10 + 10t = 5(2t + 2) + -9

Reorder the terms:
-10 + 10t = 5(2 + 2t) + -9
-10 + 10t = (2 * 5 + 2t * 5) + -9
-10 + 10t = (10 + 10t) + -9

Reorder the terms:
-10 + 10t = 10 + -9 + 10t

Combine like terms: 10 + -9 = 1
-10 + 10t = 1 + 10t

Add '-10t' to each side of the equation.
-10 + 10t + -10t = 1 + 10t + -10t

Combine like terms: 10t + -10t = 0
-10 + 0 = 1 + 10t + -10t
-10 = 1 + 10t + -10t

Combine like terms: 10t + -10t = 0
-10 = 1 + 0
-10 = 1

Solving
-10 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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