5(t-2)+7t=4(3t+3)-10

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Solution for 5(t-2)+7t=4(3t+3)-10 equation:


Simplifying
5(t + -2) + 7t = 4(3t + 3) + -10

Reorder the terms:
5(-2 + t) + 7t = 4(3t + 3) + -10
(-2 * 5 + t * 5) + 7t = 4(3t + 3) + -10
(-10 + 5t) + 7t = 4(3t + 3) + -10

Combine like terms: 5t + 7t = 12t
-10 + 12t = 4(3t + 3) + -10

Reorder the terms:
-10 + 12t = 4(3 + 3t) + -10
-10 + 12t = (3 * 4 + 3t * 4) + -10
-10 + 12t = (12 + 12t) + -10

Reorder the terms:
-10 + 12t = 12 + -10 + 12t

Combine like terms: 12 + -10 = 2
-10 + 12t = 2 + 12t

Add '-12t' to each side of the equation.
-10 + 12t + -12t = 2 + 12t + -12t

Combine like terms: 12t + -12t = 0
-10 + 0 = 2 + 12t + -12t
-10 = 2 + 12t + -12t

Combine like terms: 12t + -12t = 0
-10 = 2 + 0
-10 = 2

Solving
-10 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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