5(t-3)+3t=4(2t+3)-8

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Solution for 5(t-3)+3t=4(2t+3)-8 equation: 



5(t-3)+3t=4(2t+3)-8

We move all terms to the left:

5(t-3)+3t-(4(2t+3)-8)=0

We add all the numbers together, and all the variables

3t+5(t-3)-(4(2t+3)-8)=0

We multiply parentheses

3t+5t-(4(2t+3)-8)-15=0



We calculate terms in parentheses: -(4(2t+3)-8), so:

4(2t+3)-8

We multiply parentheses

8t+12-8

We add all the numbers together, and all the variables

8t+4

Back to the equation:

-(8t+4)



We add all the numbers together, and all the variables

8t-(8t+4)-15=0

We get rid of parentheses

8t-8t-4-15=0

We add all the numbers together, and all the variables

-19!=0

There is no solution for this equation

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