5(t-3)+4t=-2t-3

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Solution for 5(t-3)+4t=-2t-3 equation: 



5(t-3)+4t=-2t-3

We move all terms to the left:

5(t-3)+4t-(-2t-3)=0

We add all the numbers together, and all the variables

4t+5(t-3)-(-2t-3)=0

We multiply parentheses

4t+5t-(-2t-3)-15=0

We get rid of parentheses

4t+5t+2t+3-15=0

We add all the numbers together, and all the variables

11t-12=0

We move all terms containing t to the left, all other terms to the right

11t=12

t=12/11

t=1+1/11

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