5(t-4)+3t=4(2t+4)-13

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Solution for 5(t-4)+3t=4(2t+4)-13 equation:


Simplifying
5(t + -4) + 3t = 4(2t + 4) + -13

Reorder the terms:
5(-4 + t) + 3t = 4(2t + 4) + -13
(-4 * 5 + t * 5) + 3t = 4(2t + 4) + -13
(-20 + 5t) + 3t = 4(2t + 4) + -13

Combine like terms: 5t + 3t = 8t
-20 + 8t = 4(2t + 4) + -13

Reorder the terms:
-20 + 8t = 4(4 + 2t) + -13
-20 + 8t = (4 * 4 + 2t * 4) + -13
-20 + 8t = (16 + 8t) + -13

Reorder the terms:
-20 + 8t = 16 + -13 + 8t

Combine like terms: 16 + -13 = 3
-20 + 8t = 3 + 8t

Add '-8t' to each side of the equation.
-20 + 8t + -8t = 3 + 8t + -8t

Combine like terms: 8t + -8t = 0
-20 + 0 = 3 + 8t + -8t
-20 = 3 + 8t + -8t

Combine like terms: 8t + -8t = 0
-20 = 3 + 0
-20 = 3

Solving
-20 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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