5(t-4)+5t=5(2t+3)-12

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Solution for 5(t-4)+5t=5(2t+3)-12 equation:


Simplifying
5(t + -4) + 5t = 5(2t + 3) + -12

Reorder the terms:
5(-4 + t) + 5t = 5(2t + 3) + -12
(-4 * 5 + t * 5) + 5t = 5(2t + 3) + -12
(-20 + 5t) + 5t = 5(2t + 3) + -12

Combine like terms: 5t + 5t = 10t
-20 + 10t = 5(2t + 3) + -12

Reorder the terms:
-20 + 10t = 5(3 + 2t) + -12
-20 + 10t = (3 * 5 + 2t * 5) + -12
-20 + 10t = (15 + 10t) + -12

Reorder the terms:
-20 + 10t = 15 + -12 + 10t

Combine like terms: 15 + -12 = 3
-20 + 10t = 3 + 10t

Add '-10t' to each side of the equation.
-20 + 10t + -10t = 3 + 10t + -10t

Combine like terms: 10t + -10t = 0
-20 + 0 = 3 + 10t + -10t
-20 = 3 + 10t + -10t

Combine like terms: 10t + -10t = 0
-20 = 3 + 0
-20 = 3

Solving
-20 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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