5(t-4)+7t=6(2t+2)-11

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Solution for 5(t-4)+7t=6(2t+2)-11 equation:


Simplifying
5(t + -4) + 7t = 6(2t + 2) + -11

Reorder the terms:
5(-4 + t) + 7t = 6(2t + 2) + -11
(-4 * 5 + t * 5) + 7t = 6(2t + 2) + -11
(-20 + 5t) + 7t = 6(2t + 2) + -11

Combine like terms: 5t + 7t = 12t
-20 + 12t = 6(2t + 2) + -11

Reorder the terms:
-20 + 12t = 6(2 + 2t) + -11
-20 + 12t = (2 * 6 + 2t * 6) + -11
-20 + 12t = (12 + 12t) + -11

Reorder the terms:
-20 + 12t = 12 + -11 + 12t

Combine like terms: 12 + -11 = 1
-20 + 12t = 1 + 12t

Add '-12t' to each side of the equation.
-20 + 12t + -12t = 1 + 12t + -12t

Combine like terms: 12t + -12t = 0
-20 + 0 = 1 + 12t + -12t
-20 = 1 + 12t + -12t

Combine like terms: 12t + -12t = 0
-20 = 1 + 0
-20 = 1

Solving
-20 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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