5(t-7)=5t-35

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Solution for 5(t-7)=5t-35 equation: 



5(t-7)=5t-35

We move all terms to the left:

5(t-7)-(5t-35)=0

We multiply parentheses

5t-(5t-35)-35=0

We get rid of parentheses

5t-5t+35-35=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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