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5(u+1)-u=3(u-1)+1
We move all terms to the left:
5(u+1)-u-(3(u-1)+1)=0
We add all the numbers together, and all the variables
-1u+5(u+1)-(3(u-1)+1)=0
We multiply parentheses
-1u+5u-(3(u-1)+1)+5=0
We calculate terms in parentheses: -(3(u-1)+1), so:We add all the numbers together, and all the variables
3(u-1)+1
We multiply parentheses
3u-3+1
We add all the numbers together, and all the variables
3u-2
Back to the equation:
-(3u-2)
4u-(3u-2)+5=0
We get rid of parentheses
4u-3u+2+5=0
We add all the numbers together, and all the variables
u+7=0
We move all terms containing u to the left, all other terms to the right
u=-7
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