5(u+2)=-4(2u-6)+9u

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Solution for 5(u+2)=-4(2u-6)+9u equation: 



5(u+2)=-4(2u-6)+9u

We move all terms to the left:

5(u+2)-(-4(2u-6)+9u)=0

We multiply parentheses

5u-(-4(2u-6)+9u)+10=0



We calculate terms in parentheses: -(-4(2u-6)+9u), so:

-4(2u-6)+9u

We add all the numbers together, and all the variables

9u-4(2u-6)

We multiply parentheses

9u-8u+24

We add all the numbers together, and all the variables

u+24

Back to the equation:

-(u+24)



We get rid of parentheses

5u-u-24+10=0

We add all the numbers together, and all the variables

4u-14=0

We move all terms containing u to the left, all other terms to the right

4u=14

u=14/4

u=3+1/2

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