5(u+3)+2u=1+7(u-2)

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Solution for 5(u+3)+2u=1+7(u-2) equation:


Simplifying
5(u + 3) + 2u = 1 + 7(u + -2)

Reorder the terms:
5(3 + u) + 2u = 1 + 7(u + -2)
(3 * 5 + u * 5) + 2u = 1 + 7(u + -2)
(15 + 5u) + 2u = 1 + 7(u + -2)

Combine like terms: 5u + 2u = 7u
15 + 7u = 1 + 7(u + -2)

Reorder the terms:
15 + 7u = 1 + 7(-2 + u)
15 + 7u = 1 + (-2 * 7 + u * 7)
15 + 7u = 1 + (-14 + 7u)

Combine like terms: 1 + -14 = -13
15 + 7u = -13 + 7u

Add '-7u' to each side of the equation.
15 + 7u + -7u = -13 + 7u + -7u

Combine like terms: 7u + -7u = 0
15 + 0 = -13 + 7u + -7u
15 = -13 + 7u + -7u

Combine like terms: 7u + -7u = 0
15 = -13 + 0
15 = -13

Solving
15 = -13

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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