5(u+3)=3u+27

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Solution for 5(u+3)=3u+27 equation: 



5(u+3)=3u+27

We move all terms to the left:

5(u+3)-(3u+27)=0

We multiply parentheses

5u-(3u+27)+15=0

We get rid of parentheses

5u-3u-27+15=0

We add all the numbers together, and all the variables

2u-12=0

We move all terms containing u to the left, all other terms to the right

2u=12

u=12/2

u=6

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