5(u+5)=-5(2u-3)+u

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Solution for 5(u+5)=-5(2u-3)+u equation: 



5(u+5)=-5(2u-3)+u

We move all terms to the left:

5(u+5)-(-5(2u-3)+u)=0

We multiply parentheses

5u-(-5(2u-3)+u)+25=0



We calculate terms in parentheses: -(-5(2u-3)+u), so:

-5(2u-3)+u

We add all the numbers together, and all the variables

u-5(2u-3)

We multiply parentheses

u-10u+15

We add all the numbers together, and all the variables

-9u+15

Back to the equation:

-(-9u+15)



We get rid of parentheses

5u+9u-15+25=0

We add all the numbers together, and all the variables

14u+10=0

We move all terms containing u to the left, all other terms to the right

14u=-10

u=-10/14

u=-5/7

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