5(u-1)=4u+5-2(-8u-1)

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Solution for 5(u-1)=4u+5-2(-8u-1) equation: 



5(u-1)=4u+5-2(-8u-1)

We move all terms to the left:

5(u-1)-(4u+5-2(-8u-1))=0

We multiply parentheses

5u-(4u+5-2(-8u-1))-5=0



We calculate terms in parentheses: -(4u+5-2(-8u-1)), so:

4u+5-2(-8u-1)

determiningTheFunctionDomain
4u-2(-8u-1)+5

We multiply parentheses

4u+16u+2+5

We add all the numbers together, and all the variables

20u+7

Back to the equation:

-(20u+7)



We get rid of parentheses

5u-20u-7-5=0

We add all the numbers together, and all the variables

-15u-12=0

We move all terms containing u to the left, all other terms to the right

-15u=12

u=12/-15

u=-4/5

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