5(u-1)=9u+3-2(-3u-4)

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Solution for 5(u-1)=9u+3-2(-3u-4) equation: 



5(u-1)=9u+3-2(-3u-4)

We move all terms to the left:

5(u-1)-(9u+3-2(-3u-4))=0

We multiply parentheses

5u-(9u+3-2(-3u-4))-5=0



We calculate terms in parentheses: -(9u+3-2(-3u-4)), so:

9u+3-2(-3u-4)

determiningTheFunctionDomain
9u-2(-3u-4)+3

We multiply parentheses

9u+6u+8+3

We add all the numbers together, and all the variables

15u+11

Back to the equation:

-(15u+11)



We get rid of parentheses

5u-15u-11-5=0

We add all the numbers together, and all the variables

-10u-16=0

We move all terms containing u to the left, all other terms to the right

-10u=16

u=16/-10

u=-1+3/5

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