5(u-2)-7=-6(-3u+2)-3u

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Solution for 5(u-2)-7=-6(-3u+2)-3u equation: 



5(u-2)-7=-6(-3u+2)-3u

We move all terms to the left:

5(u-2)-7-(-6(-3u+2)-3u)=0

We multiply parentheses

5u-(-6(-3u+2)-3u)-10-7=0



We calculate terms in parentheses: -(-6(-3u+2)-3u), so:

-6(-3u+2)-3u

We add all the numbers together, and all the variables

-3u-6(-3u+2)

We multiply parentheses

-3u+18u-12

We add all the numbers together, and all the variables

15u-12

Back to the equation:

-(15u-12)



We add all the numbers together, and all the variables

5u-(15u-12)-17=0

We get rid of parentheses

5u-15u+12-17=0

We add all the numbers together, and all the variables

-10u-5=0

We move all terms containing u to the left, all other terms to the right

-10u=5

u=5/-10

u=-1/2

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