5(u-3)-5=-6(-2u+4)-u

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Solution for 5(u-3)-5=-6(-2u+4)-u equation: 



5(u-3)-5=-6(-2u+4)-u

We move all terms to the left:

5(u-3)-5-(-6(-2u+4)-u)=0

We multiply parentheses

5u-(-6(-2u+4)-u)-15-5=0



We calculate terms in parentheses: -(-6(-2u+4)-u), so:

-6(-2u+4)-u

We add all the numbers together, and all the variables

-1u-6(-2u+4)

We multiply parentheses

-1u+12u-24

We add all the numbers together, and all the variables

11u-24

Back to the equation:

-(11u-24)



We add all the numbers together, and all the variables

5u-(11u-24)-20=0

We get rid of parentheses

5u-11u+24-20=0

We add all the numbers together, and all the variables

-6u+4=0

We move all terms containing u to the left, all other terms to the right

-6u=-4

u=-4/-6

u=2/3

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