5(u-4)-2=-4(-4u+8)-5u

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Solution for 5(u-4)-2=-4(-4u+8)-5u equation: 



5(u-4)-2=-4(-4u+8)-5u

We move all terms to the left:

5(u-4)-2-(-4(-4u+8)-5u)=0

We multiply parentheses

5u-(-4(-4u+8)-5u)-20-2=0



We calculate terms in parentheses: -(-4(-4u+8)-5u), so:

-4(-4u+8)-5u

We add all the numbers together, and all the variables

-5u-4(-4u+8)

We multiply parentheses

-5u+16u-32

We add all the numbers together, and all the variables

11u-32

Back to the equation:

-(11u-32)



We add all the numbers together, and all the variables

5u-(11u-32)-22=0

We get rid of parentheses

5u-11u+32-22=0

We add all the numbers together, and all the variables

-6u+10=0

We move all terms containing u to the left, all other terms to the right

-6u=-10

u=-10/-6

u=1+2/3

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