5(u-4)-5=-3(-6u+3)-7u

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Solution for 5(u-4)-5=-3(-6u+3)-7u equation: 



5(u-4)-5=-3(-6u+3)-7u

We move all terms to the left:

5(u-4)-5-(-3(-6u+3)-7u)=0

We multiply parentheses

5u-(-3(-6u+3)-7u)-20-5=0



We calculate terms in parentheses: -(-3(-6u+3)-7u), so:

-3(-6u+3)-7u

We add all the numbers together, and all the variables

-7u-3(-6u+3)

We multiply parentheses

-7u+18u-9

We add all the numbers together, and all the variables

11u-9

Back to the equation:

-(11u-9)



We add all the numbers together, and all the variables

5u-(11u-9)-25=0

We get rid of parentheses

5u-11u+9-25=0

We add all the numbers together, and all the variables

-6u-16=0

We move all terms containing u to the left, all other terms to the right

-6u=16

u=16/-6

u=-2+2/3

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