5(u-5)-(u-2)=10-(2u+1)

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Solution for 5(u-5)-(u-2)=10-(2u+1) equation: 



5(u-5)-(u-2)=10-(2u+1)

We move all terms to the left:

5(u-5)-(u-2)-(10-(2u+1))=0

We multiply parentheses

5u-(u-2)-(10-(2u+1))-25=0

We get rid of parentheses

5u-u-(10-(2u+1))+2-25=0



We calculate terms in parentheses: -(10-(2u+1)), so:

10-(2u+1)

determiningTheFunctionDomain
-(2u+1)+10

We get rid of parentheses

-2u-1+10

We add all the numbers together, and all the variables

-2u+9

Back to the equation:

-(-2u+9)



We add all the numbers together, and all the variables

4u-(-2u+9)-23=0

We get rid of parentheses

4u+2u-9-23=0

We add all the numbers together, and all the variables

6u-32=0

We move all terms containing u to the left, all other terms to the right

6u=32

u=32/6

u=5+1/3

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