5(u-7)+4=2(9-u)+7

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Solution for 5(u-7)+4=2(9-u)+7 equation:



5(u-7)+4=2(9-u)+7
We move all terms to the left:
5(u-7)+4-(2(9-u)+7)=0
We add all the numbers together, and all the variables
5(u-7)-(2(-1u+9)+7)+4=0
We multiply parentheses
5u-(2(-1u+9)+7)-35+4=0
We calculate terms in parentheses: -(2(-1u+9)+7), so:
2(-1u+9)+7
We multiply parentheses
-2u+18+7
We add all the numbers together, and all the variables
-2u+25
Back to the equation:
-(-2u+25)
We add all the numbers together, and all the variables
5u-(-2u+25)-31=0
We get rid of parentheses
5u+2u-25-31=0
We add all the numbers together, and all the variables
7u-56=0
We move all terms containing u to the left, all other terms to the right
7u=56
u=56/7
u=8

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