5(v+1)-7=3-(v-1)+2v

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Solution for 5(v+1)-7=3-(v-1)+2v equation: 



5(v+1)-7=3-(v-1)+2v

We move all terms to the left:

5(v+1)-7-(3-(v-1)+2v)=0

We multiply parentheses

5v-(3-(v-1)+2v)+5-7=0



We calculate terms in parentheses: -(3-(v-1)+2v), so:

3-(v-1)+2v

determiningTheFunctionDomain
-(v-1)+2v+3

We add all the numbers together, and all the variables

2v-(v-1)+3

We get rid of parentheses

2v-v+1+3

We add all the numbers together, and all the variables

v+4

Back to the equation:

-(v+4)



We add all the numbers together, and all the variables

5v-(v+4)-2=0

We get rid of parentheses

5v-v-4-2=0

We add all the numbers together, and all the variables

4v-6=0

We move all terms containing v to the left, all other terms to the right

4v=6

v=6/4

v=1+1/2

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