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5(v+1)-v=3(v-1)+1
We move all terms to the left:
5(v+1)-v-(3(v-1)+1)=0
We add all the numbers together, and all the variables
-1v+5(v+1)-(3(v-1)+1)=0
We multiply parentheses
-1v+5v-(3(v-1)+1)+5=0
We calculate terms in parentheses: -(3(v-1)+1), so:We add all the numbers together, and all the variables
3(v-1)+1
We multiply parentheses
3v-3+1
We add all the numbers together, and all the variables
3v-2
Back to the equation:
-(3v-2)
4v-(3v-2)+5=0
We get rid of parentheses
4v-3v+2+5=0
We add all the numbers together, and all the variables
v+7=0
We move all terms containing v to the left, all other terms to the right
v=-7
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