5(v+1)-v=4(v-1)+1

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Solution for 5(v+1)-v=4(v-1)+1 equation: 



5(v+1)-v=4(v-1)+1

We move all terms to the left:

5(v+1)-v-(4(v-1)+1)=0

We add all the numbers together, and all the variables

-1v+5(v+1)-(4(v-1)+1)=0

We multiply parentheses

-1v+5v-(4(v-1)+1)+5=0



We calculate terms in parentheses: -(4(v-1)+1), so:

4(v-1)+1

We multiply parentheses

4v-4+1

We add all the numbers together, and all the variables

4v-3

Back to the equation:

-(4v-3)



We add all the numbers together, and all the variables

4v-(4v-3)+5=0

We get rid of parentheses

4v-4v+3+5=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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