5(v+1)-v=4(v-1)+9

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Solution for 5(v+1)-v=4(v-1)+9 equation:


Simplifying
5(v + 1) + -1v = 4(v + -1) + 9

Reorder the terms:
5(1 + v) + -1v = 4(v + -1) + 9
(1 * 5 + v * 5) + -1v = 4(v + -1) + 9
(5 + 5v) + -1v = 4(v + -1) + 9

Combine like terms: 5v + -1v = 4v
5 + 4v = 4(v + -1) + 9

Reorder the terms:
5 + 4v = 4(-1 + v) + 9
5 + 4v = (-1 * 4 + v * 4) + 9
5 + 4v = (-4 + 4v) + 9

Reorder the terms:
5 + 4v = -4 + 9 + 4v

Combine like terms: -4 + 9 = 5
5 + 4v = 5 + 4v

Add '-5' to each side of the equation.
5 + -5 + 4v = 5 + -5 + 4v

Combine like terms: 5 + -5 = 0
0 + 4v = 5 + -5 + 4v
4v = 5 + -5 + 4v

Combine like terms: 5 + -5 = 0
4v = 0 + 4v
4v = 4v

Add '-4v' to each side of the equation.
4v + -4v = 4v + -4v

Combine like terms: 4v + -4v = 0
0 = 4v + -4v

Combine like terms: 4v + -4v = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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