5(v+2)=-2v-32

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Solution for 5(v+2)=-2v-32 equation: 



5(v+2)=-2v-32

We move all terms to the left:

5(v+2)-(-2v-32)=0

We multiply parentheses

5v-(-2v-32)+10=0

We get rid of parentheses

5v+2v+32+10=0

We add all the numbers together, and all the variables

7v+42=0

We move all terms containing v to the left, all other terms to the right

7v=-42

v=-42/7

v=-6

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