5(v+2)=-3(2v-2)+3v

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Solution for 5(v+2)=-3(2v-2)+3v equation: 



5(v+2)=-3(2v-2)+3v

We move all terms to the left:

5(v+2)-(-3(2v-2)+3v)=0

We multiply parentheses

5v-(-3(2v-2)+3v)+10=0



We calculate terms in parentheses: -(-3(2v-2)+3v), so:

-3(2v-2)+3v

We add all the numbers together, and all the variables

3v-3(2v-2)

We multiply parentheses

3v-6v+6

We add all the numbers together, and all the variables

-3v+6

Back to the equation:

-(-3v+6)



We get rid of parentheses

5v+3v-6+10=0

We add all the numbers together, and all the variables

8v+4=0

We move all terms containing v to the left, all other terms to the right

8v=-4

v=-4/8

v=-1/2

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