5(v+2)=2(9v-4)+5v

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Solution for 5(v+2)=2(9v-4)+5v equation: 



5(v+2)=2(9v-4)+5v

We move all terms to the left:

5(v+2)-(2(9v-4)+5v)=0

We multiply parentheses

5v-(2(9v-4)+5v)+10=0



We calculate terms in parentheses: -(2(9v-4)+5v), so:

2(9v-4)+5v

We add all the numbers together, and all the variables

5v+2(9v-4)

We multiply parentheses

5v+18v-8

We add all the numbers together, and all the variables

23v-8

Back to the equation:

-(23v-8)



We get rid of parentheses

5v-23v+8+10=0

We add all the numbers together, and all the variables

-18v+18=0

We move all terms containing v to the left, all other terms to the right

-18v=-18

v=-18/-18

v=1

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