5(v+3)=9v+27

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Solution for 5(v+3)=9v+27 equation: 



5(v+3)=9v+27

We move all terms to the left:

5(v+3)-(9v+27)=0

We multiply parentheses

5v-(9v+27)+15=0

We get rid of parentheses

5v-9v-27+15=0

We add all the numbers together, and all the variables

-4v-12=0

We move all terms containing v to the left, all other terms to the right

-4v=12

v=12/-4

v=-3

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