5(v+5)=5+2(1-2v)

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Solution for 5(v+5)=5+2(1-2v) equation: 



5(v+5)=5+2(1-2v)

We move all terms to the left:

5(v+5)-(5+2(1-2v))=0

We add all the numbers together, and all the variables

5(v+5)-(5+2(-2v+1))=0

We multiply parentheses

5v-(5+2(-2v+1))+25=0



We calculate terms in parentheses: -(5+2(-2v+1)), so:

5+2(-2v+1)

determiningTheFunctionDomain
2(-2v+1)+5

We multiply parentheses

-4v+2+5

We add all the numbers together, and all the variables

-4v+7

Back to the equation:

-(-4v+7)



We get rid of parentheses

5v+4v-7+25=0

We add all the numbers together, and all the variables

9v+18=0

We move all terms containing v to the left, all other terms to the right

9v=-18

v=-18/9

v=-2

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