5(v+8)(-v+2)=0

Solution for 5(v+8)(-v+2)=0 equation:

5(v+8)(-v+2)=0

We add all the numbers together, and all the variables

5(v+8)(-1v+2)=0

We multiply parentheses ..

5(-1v^2+2v-8v+16)=0

We multiply parentheses

-5v^2+10v-40v+80=0

We add all the numbers together, and all the variables

-5v^2-30v+80=0

a = -5; b = -30; c = +80;
Δ = b2-4ac
Δ = -302-4·(-5)·80
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-50}{2*-5}=\frac{-20}{-10}
=+2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+50}{2*-5}=\frac{80}{-10}
=-8
$