5(v-1)-4=-6(-4v+1)-4v

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Solution for 5(v-1)-4=-6(-4v+1)-4v equation: 



5(v-1)-4=-6(-4v+1)-4v

We move all terms to the left:

5(v-1)-4-(-6(-4v+1)-4v)=0

We multiply parentheses

5v-(-6(-4v+1)-4v)-5-4=0



We calculate terms in parentheses: -(-6(-4v+1)-4v), so:

-6(-4v+1)-4v

We add all the numbers together, and all the variables

-4v-6(-4v+1)

We multiply parentheses

-4v+24v-6

We add all the numbers together, and all the variables

20v-6

Back to the equation:

-(20v-6)



We add all the numbers together, and all the variables

5v-(20v-6)-9=0

We get rid of parentheses

5v-20v+6-9=0

We add all the numbers together, and all the variables

-15v-3=0

We move all terms containing v to the left, all other terms to the right

-15v=3

v=3/-15

v=-1/5

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