5(v-2)-1=-5(-3v+5)-2v

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Solution for 5(v-2)-1=-5(-3v+5)-2v equation: 



5(v-2)-1=-5(-3v+5)-2v

We move all terms to the left:

5(v-2)-1-(-5(-3v+5)-2v)=0

We multiply parentheses

5v-(-5(-3v+5)-2v)-10-1=0



We calculate terms in parentheses: -(-5(-3v+5)-2v), so:

-5(-3v+5)-2v

We add all the numbers together, and all the variables

-2v-5(-3v+5)

We multiply parentheses

-2v+15v-25

We add all the numbers together, and all the variables

13v-25

Back to the equation:

-(13v-25)



We add all the numbers together, and all the variables

5v-(13v-25)-11=0

We get rid of parentheses

5v-13v+25-11=0

We add all the numbers together, and all the variables

-8v+14=0

We move all terms containing v to the left, all other terms to the right

-8v=-14

v=-14/-8

v=1+3/4

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