5(v-3)-7=-5(-6v+4)-9v

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Solution for 5(v-3)-7=-5(-6v+4)-9v equation: 



5(v-3)-7=-5(-6v+4)-9v

We move all terms to the left:

5(v-3)-7-(-5(-6v+4)-9v)=0

We multiply parentheses

5v-(-5(-6v+4)-9v)-15-7=0



We calculate terms in parentheses: -(-5(-6v+4)-9v), so:

-5(-6v+4)-9v

We add all the numbers together, and all the variables

-9v-5(-6v+4)

We multiply parentheses

-9v+30v-20

We add all the numbers together, and all the variables

21v-20

Back to the equation:

-(21v-20)



We add all the numbers together, and all the variables

5v-(21v-20)-22=0

We get rid of parentheses

5v-21v+20-22=0

We add all the numbers together, and all the variables

-16v-2=0

We move all terms containing v to the left, all other terms to the right

-16v=2

v=2/-16

v=-1/8

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