5(v-3)v-3=5

Solution for 5(v-3)v-3=5 equation:

5(v-3)v-3=5

We move all terms to the left:

5(v-3)v-3-(5)=0

We add all the numbers together, and all the variables

5(v-3)v-8=0

We multiply parentheses

5v^2-15v-8=0

a = 5; b = -15; c = -8;
Δ = b2-4ac
Δ = -152-4·5·(-8)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{385}}{2*5}=\frac{15-\sqrt{385}}{10}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{385}}{2*5}=\frac{15+\sqrt{385}}{10}
$