5(v-4)-2=-4(-5v+5)-v

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Solution for 5(v-4)-2=-4(-5v+5)-v equation: 



5(v-4)-2=-4(-5v+5)-v

We move all terms to the left:

5(v-4)-2-(-4(-5v+5)-v)=0

We multiply parentheses

5v-(-4(-5v+5)-v)-20-2=0



We calculate terms in parentheses: -(-4(-5v+5)-v), so:

-4(-5v+5)-v

We add all the numbers together, and all the variables

-1v-4(-5v+5)

We multiply parentheses

-1v+20v-20

We add all the numbers together, and all the variables

19v-20

Back to the equation:

-(19v-20)



We add all the numbers together, and all the variables

5v-(19v-20)-22=0

We get rid of parentheses

5v-19v+20-22=0

We add all the numbers together, and all the variables

-14v-2=0

We move all terms containing v to the left, all other terms to the right

-14v=2

v=2/-14

v=-1/7

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