5(v-4)=-2v+22

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Solution for 5(v-4)=-2v+22 equation: 



5(v-4)=-2v+22

We move all terms to the left:

5(v-4)-(-2v+22)=0

We multiply parentheses

5v-(-2v+22)-20=0

We get rid of parentheses

5v+2v-22-20=0

We add all the numbers together, and all the variables

7v-42=0

We move all terms containing v to the left, all other terms to the right

7v=42

v=42/7

v=6

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