5(w+2)-11=2w-(-9+7w)

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Solution for 5(w+2)-11=2w-(-9+7w) equation: 



5(w+2)-11=2w-(-9+7w)

We move all terms to the left:

5(w+2)-11-(2w-(-9+7w))=0

We add all the numbers together, and all the variables

5(w+2)-(2w-(7w-9))-11=0

We multiply parentheses

5w-(2w-(7w-9))+10-11=0



We calculate terms in parentheses: -(2w-(7w-9)), so:

2w-(7w-9)

We get rid of parentheses

2w-7w+9

We add all the numbers together, and all the variables

-5w+9

Back to the equation:

-(-5w+9)



We add all the numbers together, and all the variables

5w-(-5w+9)-1=0

We get rid of parentheses

5w+5w-9-1=0

We add all the numbers together, and all the variables

10w-10=0

We move all terms containing w to the left, all other terms to the right

10w=10

w=10/10

w=1

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