5(w+2)-4(3w-12)=2(6w-7)-5(3w+6)

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Solution for 5(w+2)-4(3w-12)=2(6w-7)-5(3w+6) equation:



5(w+2)-4(3w-12)=2(6w-7)-5(3w+6)
We move all terms to the left:
5(w+2)-4(3w-12)-(2(6w-7)-5(3w+6))=0
We multiply parentheses
5w-12w-(2(6w-7)-5(3w+6))+10+48=0
We calculate terms in parentheses: -(2(6w-7)-5(3w+6)), so:
2(6w-7)-5(3w+6)
We multiply parentheses
12w-15w-14-30
We add all the numbers together, and all the variables
-3w-44
Back to the equation:
-(-3w-44)
We add all the numbers together, and all the variables
-7w-(-3w-44)+58=0
We get rid of parentheses
-7w+3w+44+58=0
We add all the numbers together, and all the variables
-4w+102=0
We move all terms containing w to the left, all other terms to the right
-4w=-102
w=-102/-4
w=25+1/2

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