5(w-15)+1=4w+6(w-2)

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Solution for 5(w-15)+1=4w+6(w-2) equation: 



5(w-15)+1=4w+6(w-2)

We move all terms to the left:

5(w-15)+1-(4w+6(w-2))=0

We multiply parentheses

5w-(4w+6(w-2))-75+1=0



We calculate terms in parentheses: -(4w+6(w-2)), so:

4w+6(w-2)

We multiply parentheses

4w+6w-12

We add all the numbers together, and all the variables

10w-12

Back to the equation:

-(10w-12)



We add all the numbers together, and all the variables

5w-(10w-12)-74=0

We get rid of parentheses

5w-10w+12-74=0

We add all the numbers together, and all the variables

-5w-62=0

We move all terms containing w to the left, all other terms to the right

-5w=62

w=62/-5

w=-12+2/5

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