5(w-3)(w-6)=0

Solution for 5(w-3)(w-6)=0 equation:

5(w-3)(w-6)=0

We multiply parentheses ..

5(+w^2-6w-3w+18)=0

We multiply parentheses

5w^2-30w-15w+90=0

We add all the numbers together, and all the variables

5w^2-45w+90=0

a = 5; b = -45; c = +90;
Δ = b2-4ac
Δ = -452-4·5·90
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-15}{2*5}=\frac{30}{10}
=3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+15}{2*5}=\frac{60}{10}
=6
$