5(w-6)(-w-2)=0

Solution for 5(w-6)(-w-2)=0 equation:

5(w-6)(-w-2)=0

We add all the numbers together, and all the variables

5(w-6)(-1w-2)=0

We multiply parentheses ..

5(-1w^2-2w+6w+12)=0

We multiply parentheses

-5w^2-10w+30w+60=0

We add all the numbers together, and all the variables

-5w^2+20w+60=0

a = -5; b = 20; c = +60;
Δ = b2-4ac
Δ = 202-4·(-5)·60
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-40}{2*-5}=\frac{-60}{-10}
=+6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+40}{2*-5}=\frac{20}{-10}
=-2
$