5(x)+10(40-x)=290

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Solution for 5(x)+10(40-x)=290 equation: 



5(x)+10(40-x)=290

We move all terms to the left:

5(x)+10(40-x)-(290)=0

We add all the numbers together, and all the variables

5x+10(-1x+40)-290=0

We multiply parentheses

5x-10x+400-290=0

We add all the numbers together, and all the variables

-5x+110=0

We move all terms containing x to the left, all other terms to the right

-5x=-110

x=-110/-5

x=+22

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