If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5(x)=-12x^2+5x
We move all terms to the left:
5(x)-(-12x^2+5x)=0
We get rid of parentheses
12x^2-5x+5x=0
We add all the numbers together, and all the variables
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{24}=0$
| 7x-11+142=180 | | 9u+33=-3(u+1) | | 2x*x-30=0 | | -7(y+6)=-3y-26 | | 5a+6-2a=4a-8 | | 8=8082x-1 | | 1/x+1√2=650 | | 5m=-124 | | 2y-6=-6(y-1) | | 5m=-225 | | 3x–7=-13 | | 5(6m-10)=-10 | | 005x+2=10004x−1 | | 3v=32 | | 20x^2-90x=0 | | (5/8)y=9 | | 8x-2=-64 | | 4x-7=-2x+12 | | 3t–2=13 | | 7a-10=25 | | 2t+7=-11 | | F(x)=2x^2-14x+20 | | -5.4-7.8x=-8.408 | | -445+7(x5−3x2)=3(x5−7x2) | | (2.4x3+3.2x−1)(1.2x3+0.8x+4.3)=2 | | -59−8(x3+x2)=8x2+5(x3+2) | | 5(x2+x2)+2=7(x2+x2+1) | | 24-(8x+3=-6(3x-4)-13 | | 4(3x+1)-2x=3(2x+3)+15 | | 19=-4y-(3-4y)+3 | | 7x+8+2x3=-7 | | 2(x-7)+3=8x-17 |