5(x+)=4(x-3)

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Solution for 5(x+)=4(x-3) equation: 



5(x+)=4(x-3)

We move all terms to the left:

5(x+)-(4(x-3))=0

We add all the numbers together, and all the variables

5(+x)-(4(x-3))=0

We multiply parentheses

5x-(4(x-3))=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

5x-4x+12=0

We add all the numbers together, and all the variables

x+12=0

We move all terms containing x to the left, all other terms to the right

x=-12

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