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5(x+)=4(x-3)
We move all terms to the left:
5(x+)-(4(x-3))=0
We add all the numbers together, and all the variables
5(+x)-(4(x-3))=0
We multiply parentheses
5x-(4(x-3))=0
We calculate terms in parentheses: -(4(x-3)), so:We get rid of parentheses
4(x-3)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
5x-4x+12=0
We add all the numbers together, and all the variables
x+12=0
We move all terms containing x to the left, all other terms to the right
x=-12
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