5(x+-3)=10(x+-2)

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Solution for 5(x+-3)=10(x+-2) equation: 



5(x+-3)=10(x+-2)

We move all terms to the left:

5(x+-3)-(10(x+-2))=0

We add all the numbers together, and all the variables

5(x-3)-(10(x-2))=0

We multiply parentheses

5x-(10(x-2))-15=0



We calculate terms in parentheses: -(10(x-2)), so:

10(x-2)

We multiply parentheses

10x-20

Back to the equation:

-(10x-20)



We get rid of parentheses

5x-10x+20-15=0

We add all the numbers together, and all the variables

-5x+5=0

We move all terms containing x to the left, all other terms to the right

-5x=-5

x=-5/-5

x=1

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